7 клас

Самостійна робота

До теми: Метали й неметали

I варіант

1. Хімічна формула простої речовини заліза:

а) Fе₃;                                                                                                                                                                                                                                                                                                                                           б) FеО;                                                                                                                                                                                                                                                                                                                         в) Fе.

2.Формула ферум (III) оксиду:

а) Fе₃О₄;                                                                                                                                                                                                                                                                                   б) Fе₂О₃;                                                                                                                                                                                                                                                                                    в) FеО.

3. Закінчити рівняння реакцій:

а)   Fе (III)  + О₂ ->

б)   Fе(III) + СІ₂ ->

в)   Fе₂О₃ + СO₂->

4. Масова частка Феруму у ферум (II) оксиді:

а) 77,8%;                                                                                                                                                                                                                                                                           б) 70%;                                                                                                                                                                                                                                                                                                                     в) 79,4%.

5.  Дано рівняння реакції:

        Fе + О₂ -» Fе₃О₄

Сума коефіцієнтів у рівнянні:

а) 3;    б) 9;    в) 6.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                        6. Використовується у техніці:

а) Ферум;                                                                                                                                                                                                                                                                  б) залізо.

II варіант

1. Хімічний символ елемента Ферум:

а) Lі;                                                                                                                                                                                                                                                                                                                                                                      б) Fе;                                                                                                                                                                                                                                                                                                                                                               в) Мn.

2. Формула ферум (II) оксиду:

а) Fе₃О₄;                                                                                                                                                                                                                                                                                     б) Fе₂О₃;                                                                                                                                                                                                                                                                                      в) FеО.

3. Закінчити рівняння реакцій:

а)   Fе (II)  + S ->

б)   Fе(III) + СІ₂ ->

в)   Fе₃О₄ + СO->

4.  Масова частка Феруму у ферум (III) оксиді:

а) 77,8%;                                                                                                                                                                                                                                                                            б) 70%;                                                                                                                                                                                                                                                                                                                    в) 72,4%.

5. Дано рівняння реакції:

Fе + О₂ -» Fе₂О₃

Сума коефіцієнтів у рівнянні:

а) 3;   б) 6;    в) 9.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                

6. Зустрічається в природі у вигляді оксидів, сульфідів та ін.

а) залізо;                                                                                                                                                                                                                                                                            б) Ферум.